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A French club collected the same amount from each student going on a trip. When six students could not go, each of the remaining students was charged 3 dollars extra. If the total cost was $540, how many students went on the trip?

So far I've got Let x=The amount of students. x-6

Spencer Whitney
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  • The idea is probably that the group of French students travelled for a fixed total cost. So initially (N + 6) students would travel, at a cost C per person. But actually N travelled at a cost of (C + 3) per person. Given that the total cost is $540, you can determine N and C. – M. Wind Nov 16 '14 at 23:54

1 Answers1

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Assuming that the cost of the trip is constant, you can make two equations based on $x$, the total number of students in the class, and $y$, the cost per student when all the students were going on the trip.

From this it is easy to see that $xy=540$, because $x$ students would each pay $y$ dollars to go on the trip.

Given 6 less students, each paying 3 dollars less, the equation becomes $(x-6)(y-3) = 540$, because the cost of the trip remains the same.

Hopefully you can see that this is a nice system of equations for you to solve.

Stretch Maniac
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