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Is open connected subset of $ \mathbb{R^2} $ is path connected?

slinshady
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2 Answers2

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Hint: Prove any path component must be both open and closed.

user2345215
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Hint: The answer is yes.

To prove it, call $U$ the connected, open set, and choose a point $x$ inside. Consider $U'=\{y\in U:\text{ there exists a path from $x$ to $y$}\}$. Prove that $U'$ is open and closed in $U$.

The fact that open balls are path connected will come in handy.

ajotatxe
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