I know that the square root is defined for positive operators, i.e, a square root of a positive operator $A$ is a self-adjoint operator $B$ satisfying $B^2 = A$
If $A$ is an arbitrary positive definite matrix $2×2$, then what is $\sqrt A$?
I know that the square root is defined for positive operators, i.e, a square root of a positive operator $A$ is a self-adjoint operator $B$ satisfying $B^2 = A$
If $A$ is an arbitrary positive definite matrix $2×2$, then what is $\sqrt A$?