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Let $A$ be a matrix whose rows are pmfs (i.e. nonnegative entries, each row sums to $1$). Are there any conditions on $A$ weaker than invertibility such that $AA^t$ is invertible?

egreg
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anonymous
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1 Answers1

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In general, $AA'$ is invertible iff $A$ has full row rank.

For convenience, let $B=A'$, then we are to investigate $B'B$, which is positive semidefinite. Then, $$ B'B\text{ is invertible}\iff B'B\text{ is positive definite}\\ \iff\forall v\neq 0, 0<v'B'Bv=|Bv|^2\\ \iff\forall v\neq 0, Bv\neq 0\iff B\text{ has full column rank.} $$ (Every $v$ above is a column vector with length equals to the number of columns of $B$.)

Kim Jong Un
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