Why is a set of functions $v(t)$ dense in $L^2$

Asked Dec 09 '14 at 00:34

Active Dec 09 '14 at 00:40

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I was going through the following paper: http://www.emis.de/journals/HOA/AAA/Volume2011/142128.pdf

In page 6, immediately after equation (3.15), its written that "functions of the form $v(t)$ are dense in $L^2\,$". I have been looking for proofs online which verifies the above statement but unable to find one. I would appreciate if someone can direct me to a link or explain with PROOF of how the functions of the form $v(t)$ are dense in $L^2$.

Thank you,

edited Dec 09 '14 at 00:40

Kola B.

2,465

asked Dec 09 '14 at 00:34

Sara

Can you at least briefly describe what the functions are? It it best if questions are mostly self-contained. – Mariano Suárez-Álvarez Dec 09 '14 at 00:43

Why is a set of functions $v(t)$ dense in $L^2$

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