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What is the Fourier transform of $\frac{x}{\sin(x)}$? (Not $\frac{\sin(x)}{x}$!)

Nikolaj-K
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SteveB
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    Welcome to Math.SE ! Please share your insights on the questions with us. What have you tried ? If you don't have any clue, can you explain in a few words what you know about the Fourier transform ? Doing this will decuplate the chances that someone gets interested in your questions and helps you ! :) – Traklon Dec 11 '14 at 08:04

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$x/\sin x$ is not an integrable function, so that the Fourier transform is not defined. Moreover it is not locally integrable, so that the Fourier transform is not defined even as distribution.

Julián Aguirre
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