if$\text{ } f:D(0,1)\longrightarrow D(0,1)$
is analytic such that there exists
$a,b\in D(0,1)$ and $\text{ }$$f(a)=a$ , $f(b)=b$
prove that $f(z)=z$ $\forall$ $z\in D(0,1)$
if$\text{ } f:D(0,1)\longrightarrow D(0,1)$
is analytic such that there exists
$a,b\in D(0,1)$ and $\text{ }$$f(a)=a$ , $f(b)=b$
prove that $f(z)=z$ $\forall$ $z\in D(0,1)$