If we have $4$ Real matrices $A,B,C,D$, is it possible to show that $(A+Bi)(C+Di) = E+Fi$ in $3$ nxn matrix multiplications?
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Same as for real numbers $a,b,c,d$:
$$(a+ib)(c+id)=(ac-bd)+i(ad+bc)$$
And with $(a+b)(c+d)=(ac+bd)+(ad+bc)=t$ and $u=ac$, $v=bd$, you have then that
$$(a+ib)(c+id)=(u-v)+i(t-u-v)$$
We didn't use commutativity (except for $i$, but it won't hurt as it's also a scalar in your case), hence it works for matrices too.
This is just a variation on Karatsuba algorithm.
Jean-Claude Arbaut
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