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I don't understand the second line of the following expression. Why does he use conditional expectation? and can you explain the following calculation process to me? Thanks.

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eric
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1 Answers1

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Do you agree with the following(?): \begin{align} \text{Pr}\left( (X_{1}^{\star} - X_{2}^{\star}) (Y_{1}^{\star} - Y_{3}^{\star})>0 \right) &= \sum_{X_{1}^{\star}, Y_{1}^{\star}} \text{Pr}\left( (X_{1}^{\star} - X_{2}^{\star}) (Y_{1}^{\star} - Y_{3}^{\star})>0\; \vert\; X_{1}^{\star}, Y_{1}^{\star} \right) \cdot \text{Pr}\left( X_{1}^{\star}, Y_{1}^{\star} \right)\\ &= \text{E}_{X_{1}^{\star}, Y_{1}^{\star}} \left[\text{Pr}\left( (X_{1}^{\star} - X_{2}^{\star}) (Y_{1}^{\star} - Y_{3}^{\star})>0\; \vert\; X_{1}^{\star}, Y_{1}^{\star} \right)\right] \end{align} To verify that, you may want to check the "Law of total probability".

For the next step, you have to think the following: When does it hold that $(X_{1}^{\star} - X_{2}^{\star}) (Y_{1}^{\star} - Y_{3}^{\star})>0$? There are two cases:

  • Either $Y_{3}^{\star} \le Y_{1}^{\star}$ and $X_{2}^{\star} \le X_{1}^{\star}$ simultaneously, or
  • Either $Y_{3}^{\star} > Y_{1}^{\star}$ and $X_{2}^{\star} > X_{1}^{\star}$ simultaneously.

Recall that $X_{1}^{\star}$ and $Y_{1}^{\star}$ are now constants (given). We also know that $X_{i}^{\star}$ and $Y_{i}^{\star}$ have marginals that are uniform between $0$ and $1$. Now, I suspect that $X_{i}^{\star}$ and $X_{j}^{\star}, Y_{k}^{\star}$ for $i \neq k, i\neq j$ are independent (because they have a different subscript - am I wrong?) If I am correct, then taking into account the fact that $X_{i}^{\star}$ is uniformly distributed on $(0,1)$, we have $$ \text{Pr}(X_{2}^{\star} > X_{1}^{\star}) = (1 - X_{1}^{\star}), \quad \text{and} \quad \text{Pr}(X_{2}^{\star} \le X_{1}^{\star}) = X_{1}^{\star}. $$ Similarly, for $Y_{3}^{\star}$.

Then, the third step follows from the linearity of expectation and the next by the definition of covariance. Note that the expected value of both $X_{i}^{\star}$ and $Y_{i}^{\star}$ is equal to $1/2$.

megas
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  • Thanks very much for your detail explanation, but I still don't understand the third step. Why does the second step equal the third step? Thanks again! – eric Dec 20 '14 at 02:14
  • I have edited my answer to include more detail. There is an assumption that was not stated in the text you posted, but I have a hunch it might be stated in the part that was not posted! Let me know if that helps. – megas Dec 20 '14 at 02:26
  • Thanks a millón for your help, I understand your meaning! Thanks! – eric Dec 20 '14 at 02:36
  • Can you help me to solve this question? thanks http://math.stackexchange.com/questions/1075166/how-to-calculate-the-following-conditional-expectation-is-my-calculation-proces – eric Dec 20 '14 at 02:41