How can one find $$ L[x_0,x_1,..,x_n;\frac{1}{x+a}]?$$ The original problem asks for $$ L[x_0,x_1,..,x_n;\frac{x^{n+1}}{x\pm 1}]$$ I know there is a formula for $[x_0,x_1,..,x_n,\frac{f(x)}{a-x}]$, but I suppose it does not help.
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You mean "other than by plugging $f(x)=1/(x+a)$ into the Lagrange interpolation formula? Not clear what answer you expect. – Dec 20 '14 at 21:54
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I think there has to be a quick method for finding the coefficients of the polynomial without having to use the general formula. – user42768 Dec 20 '14 at 22:20