If I have the equation $9x^2-4y^2-72x=0 $ and I know that is a hyperbola, how would I find the standard form for this equation? I'm not sure how to convert this equation to the standard form of a hyperbola.
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$9(x^2-8x) - 4y^2 = 0 \to 9(x-4)^2 - 4y^2 = 12^2 \to \dfrac{(x-4)^2}{4^2} - \dfrac{y^2}{6^2} = 1$.
DeepSea
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Thank you! How do I find the foci? – Dec 24 '14 at 04:35
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the center is $C = (4,0)$, and $c = \sqrt{a^2+b^2} = \sqrt{4^2+6^2} = \sqrt{52} = 2\sqrt{13}\to F_1 = (4+2\sqrt{13},0), F_2 = (4-2\sqrt{13},0)$. – DeepSea Dec 24 '14 at 04:49