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I know the $\min\{x,y\}$ means the minimum value of $x$ and $y$. and it can be expressed as, $\min\{x,y\}= \frac12\left( x+y-\sqrt{(x-y)^2}\right)$

Jihad
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Sumit Roy
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  • Sorry but we are not able to understand your question. Please consider using Math jax, here's the tutorial! http://meta.math.stackexchange.com/questions/5020/mathjax-basic-tutorial-and-quick-reference – Someone Dec 31 '14 at 12:20

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By symmetry, assume $r>s$. There is the solution $(7,2)$ when $r^2-s^2=45$ Otherwise, $$r^2-s^2\geq50\\ 5s\geq485\\ s\geq97\\ r\geq98\\ (r^2-s^2)^2-5s\geq(2r-1)^2-5r=4r^2-9r+1>3r^2>2015 $$

Empy2
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