if $\alpha$, $\beta$ and $\gamma$ are the roots of equation $x^3-3x^2+3x+7=0$ ($\omega$ is the cube root of unity),then
$\frac{{\alpha}-1}{{\beta}-1}$+$\frac{{\beta}-1}{{\gamma}-1}$+$\frac{{\gamma}-1}{{\alpha}-1}$ is
(a)$\frac{3}{{\omega}}$ (b) ${\omega}^2$ (c) 2${\omega}^2$ (d) 3${\omega}^2$
The question is from the IIT entrance Exam practice material. The Answer marked in the solution booklet is (a) but I am unable to find the way to get it. Please help me out.
Thanks in Advance.