Note that one has:
$$(\mathcal{N}\Omega)^\perp=\overline{\mathcal{R}\Omega^*}=\overline{\mathcal{R}|\Omega|}$$
Denote embeddings:
$$J^0_\overline{\mathcal{R}\Omega^*}\in\mathcal{B}\big(\overline{\mathcal{R}\Omega^*},\mathcal{H}_0\big):\quad\big(J^0_\overline{\mathcal{R}\Omega^*}\big)^*\big(J^0_\overline{\mathcal{R}\Omega^*}\big)=1_\overline{\mathcal{R}\Omega^*}$$
$$J_\overline{\mathcal{R}\Omega}\in\mathcal{B}\big(\overline{\mathcal{R}\Omega},\mathcal{H}\big):\quad\big(J_\overline{\mathcal{R}\Omega}\big)^*\big(J_\overline{\mathcal{R}\Omega}\big)=1_\overline{\mathcal{R}\Omega}$$
Restrict Hamiltonians:
$$H^0_\overline{\mathcal{R}\Omega^*}:=\big(J^0_\overline{\mathcal{R}\Omega^*}\big)^*H_0\big(J^0_\overline{\mathcal{R}\Omega^*}\big)\quad H_\overline{\mathcal{R}\Omega}=\big(J_\overline{\mathcal{R}\Omega}\big)^*H\big(J_\overline{\mathcal{R}\Omega}\big)$$
By reducibility one has:*
$$\big(H^0_\overline{\mathcal{R}\Omega^*}\big)=\big(H^0_\overline{\mathcal{R}\Omega^*}\big)^*\quad\big(H_\overline{\mathcal{R}\Omega}\big)=\big(H_\overline{\mathcal{R}\Omega}\big)^*$$
Polar decomposition:
$$\Omega=J_\Omega|\Omega|:\quad(J_\Omega)^*(J_\Omega)=1_\overline{\mathcal{R}\Omega^*}\quad(J_\Omega)(J_\Omega)^*=1_\overline{\mathcal{R}\Omega}$$
Denote unitary map:
$$U_\Omega:\overline{\mathcal{R}\Omega^*}\to\overline{\mathcal{R}\Omega}:\quad U_\Omega\varphi:=J_\Omega\varphi$$
By unitarity one has:**
$$\big(J_\overline{\mathcal{R}\Omega}\big)^*U(t)\big(J_\overline{\mathcal{R}\Omega}\big)\big(U_\Omega\big)=\big(U_\Omega\big)\big(J^0_\overline{\mathcal{R}\Omega^*}\big)^*U_0(t)\big(J^0_\overline{\mathcal{R}\Omega^*}\big)$$
By Stone's theorem:
$$\big(H_\overline{\mathcal{R}\Omega}\big)=(U_\Omega)\big(H^0_\overline{\mathcal{R}\Omega^*}\big)(U_\Omega)^*$$
Concluding equivalence.
*See the thread: Reducibility
**See the thread: Unitarity