When working on Linear programming problems, we use a consistent approach by attempting to:
- Evaluate the objective function $C$ for each labeled point in the feasible region
- Pick points on the region endpoints and points inside the region.
- At which labeled point does the maximum value of $C$ occur? At which labeled point
does the minimum value of $C$ occur?
- What are the maximum and minimum values of $C$ on the entire feasible region?
- Try other constraints using points in the region to see if you can find values $x$ of $C$ that are greater or lesser than those you $y$ found.
Lets try this approach on your problem. If we draw the first two constraints ($0 \le x \le 6, 0 \le y \le 6$), we have the feasible region:

If we then add the last two constraints, the feasible region (the top left cutout is from $y \le 2x + 4$ and the bottom left cutout is from $y \ge -2x + 4$) is:

Now, we want to maximize:
$$C(x, y) = 3x + y$$
We can test each of the vertices as:
- $C(2, 0) = 6$
- $C(6, 0) = 18$
- $C(0, 4) = 4$
- $C(1, 6) = 9$
- $C(6, 6) = 24$
- Per the approach described above, we can also test points inside the region and see that they will not provide a maximum.
It is clear which is the maximum.
We could have also noted that the function $3x + y$ is increasing for positive $x$ and $y$ and from the feasible region plot, the max is given by $(x, y) = (6, 6)$. The same technique can be used to determine the minimum point.