That is $\frac{x_1^2}{\sum x_i^2} \frac{y_1}{x_1} + \frac{x_2^2}{\sum x_i^2} \frac{y_2}{x_2} + ... + \frac{x_n^2}{\sum x_i^2} \frac{y_n}{x_n}$. Isn't that a weighted average of the $\frac{y_i}{x_i}$'s?
– KittyLFeb 25 '15 at 11:39
Beta coefficients can be b=ΣxY/Σx^2, after manipulation. Only Y is not a deviated value here. So, it is a weight. But I am not sure if it is a mean.
– user2986288Feb 25 '15 at 11:55
1 Answers1
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No, since the coefficient is the slope of line which minimizes the sum of squared residuals. In that sense it cannot be interpreted as the as the mean, you should rather interpret it as the marginal impact of X on Y.