I wonder how can I interpret the binomial coefficient by using the interpretation that the binomial coefficient give us the number of subsets with k elements
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With such an interpretation, what would the final sum of all terms represent? – hardmath Feb 26 '15 at 05:53
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That´s right, dude. – HeMan Feb 26 '15 at 06:00
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See the last paragraph of this answer: http://math.stackexchange.com/a/643549/1242 – Hans Lundmark Feb 26 '15 at 06:59
2 Answers
The Binomial Theorem states that if $x, y \in \mathbb{R}$ and $n$ is a non-negative integer, then $$(x + y)^n = \sum_{k = 0}^n \binom{n}{k}x^{n - k}y^k$$ Each term is formed by selecting either an $x$ or a $y$ from each of the $n$ factors. The coefficient of $x^{n - k}y^{k}$ is the number of ways of selecting a $y$ from $k$ of the $n$ factors.
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We have $$ (1+x)^n=\overbrace{(1+x)(1+x)\cdots(1+x)}^{n\text{ factors}} $$ To compute how many terms of $x^k$ are contributed by applying the distributive property, count the number of ways to choose the $k$ factors that contribute an $x$ and the $n-k$ that contribute a $1$ out of the $n$ factors. This gives $$ \binom{n}{k}x^k $$ Summing over the possible values of $k$ gives $$ (1+x)^n=\sum_{k=0}^n\binom{n}{k}x^k $$
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