How do you find the vector of length 2 in ℝ2 making an angle of 30∘ with the x-axis?
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say (x,y) is the vector you are looking for. it have to fulfill both:
- sqrt(x^2 + y^2) = 2
- tan(30) = y/x
then just solve the system
avim
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1as @Famous Blue Raincoat said, see: http://math.stackexchange.com/a/149435/156457 Ask if it still not clear – avim Mar 02 '15 at 00:29
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$|v| = 2 \Rightarrow v = 2(\cos t, \sin t)$
$i = (1,0)$
$v \cdot (± i) = |v| \cdot |±i| \cdot \cos 30°$
$2(\cos t, \sin t) \cdot (±1, 0) = 2 \cdot 1 \cdot \frac{\sqrt{3}}{2}$
$± \cos t + 0 = \frac{\sqrt{3}}{2}$
$\cos t = ± \frac{\sqrt{3}}{2}$
$\cos^2t + \sin^2t = 1$
$\sin t = ± 1 / 2$
There are four vectors. [++], [+-], [-+], [--]
Vinícius Ferraz
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