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How do you find the vector of length 2 in ℝ2 making an angle of 30∘ with the x-axis?

2 Answers2

1

say (x,y) is the vector you are looking for. it have to fulfill both:

  1. sqrt(x^2 + y^2) = 2
  2. tan(30) = y/x

then just solve the system

avim
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$|v| = 2 \Rightarrow v = 2(\cos t, \sin t)$

$i = (1,0)$

$v \cdot (± i) = |v| \cdot |±i| \cdot \cos 30°$

$2(\cos t, \sin t) \cdot (±1, 0) = 2 \cdot 1 \cdot \frac{\sqrt{3}}{2}$

$± \cos t + 0 = \frac{\sqrt{3}}{2}$

$\cos t = ± \frac{\sqrt{3}}{2}$

$\cos^2t + \sin^2t = 1$

$\sin t = ± 1 / 2$

There are four vectors. [++], [+-], [-+], [--]