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Write the equation of the circle with center at (-1,3) and passes through the point (2,-4).

Deniz
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1 Answers1

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the distance between the center and any point on the circle is the diameter of it so :

$r = \sqrt{(2-(-1))^2+(-4-3)^2} = $

then your equation is

$(x-x_0)^2 + (y-y_0)^2=r^2$

$(x+1)^2+(y-3)^2=r^2$

chouaib
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    while I do understand that this is a low quality question, downVoting an existing answer should always be related to the content of it. Is it wrong or by any means out of context what is shown in the answer? – chouaib Mar 02 '15 at 02:00