I read in a set of memoranda that if $ \frac{b-x}{x}=\frac{b}{a}$, then $$x = \frac{ab}{a+b}$$ How is this true? I tried working it out but I could not understand. Please help.
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You have
$$\frac{b-x}{x} = \frac{b}{a} \Leftrightarrow b-x = x \frac{b}{a}$$
That implies
$$b = x\left(1+\frac{b}{a}\right)$$
And finally, you get
$$x= \frac{b}{1+\frac{b}{a}}$$
And it's the same as
$$x= \frac{ab}{a+b}$$
N. F. Taussig
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Tryss
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$$\frac{b-x}{x} = \frac{b}{x} - 1 $$ I think this is the step you're looking for : $$\frac{b-x}{x} = \frac{b}{a}$$
$$\frac{b}{x} = \frac{b}{a}+1 = \frac{a+b}{a}$$
I think you're now able to do it...
Tlön Uqbar Orbis Tertius
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Still cant see the link – Aspiring Mathlete Mar 05 '15 at 18:11