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For positive reals $a,b,c$ prove $$\frac{a+b-2c}{b+c} +\frac{b+c-2a}{c+a} + \frac{c+a-2b}{a+b}\geq 0$$

I proved this if these $a,b,c$ were sides of a triangle but could not proceed further

AMPerrine
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1 Answers1

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Hint: Note that $$\prod_{cyc}(b+c) \sum_{cyc}\frac{a+b-2c}{b+c} = \sum_{cyc} a(a-c)^2$$

Macavity
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