Why is the maximum number of integer values per fixed-length variable sightly more than the amount of values for the previous one squared?

Question

For example; an 8-bit variable can have 255 total values. 255 squared is 65,025, but the amount of total values for a 16-bit variable is 65,536. Where do these extra 511 values come from?

score 1 · Accepted Answer · answered Mar 12 '15 at 23:44

1

Actually an 8 bit variable can have $2^8=256$ values and a $16$ bit one can have $2^{16}=65536=256^2$ different values.

answered Mar 12 '15 at 23:44

Ross Millikan

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Why is the maximum number of integer values per fixed-length variable sightly more than the amount of values for the previous one squared?

1 Answers1