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I have to calculate number of roots of the quation $6\ln(x^2+1)=e^x$. $(6\ln(x^2+1) - e^x)^{'} = \frac{12x}{x^2+1} - e^x$. It's not easy to examine sign of $\frac{12x}{x^2+1} - e^x$. So, what should I do?

alex
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1 Answers1

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Hint: plot the graph of $y=6\log(x^2+1)$ and the graph of $y=e^x$ and look at the common points.

Emilio Novati
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