Why isn't the answer for this 9? If it is different how do I do it? Thanks in advance.!
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3They want the lowest value of *n* such that $c_n$ is nonzero. – Ben Grossmann Mar 27 '15 at 23:41
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And indeed, it is not $9$. – Clement C. Mar 27 '15 at 23:45
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$\displaystyle f(x)=9x^2\left[x^{10}-\frac{x^{30}}{3}+\frac{x^{50}}{5}-\cdots\right]=9x^{12}-3x^{32}+\frac{9}{5}x^{52}-\cdots,$
so $\;9x^{12}$ is the nonzero term of lowest degree.
user84413
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Thanks for letting me know; I guess Omnomnomnom was right about what they were asking for, and he worded the question better. – user84413 Mar 28 '15 at 16:01