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How do you show that $4^\frac{1}{3}$ is an algebraic number?

I don't understand the question nor how to begin on describing the proof to show what the question is asking.

Chappers
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DaGuruDot
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    By definition a number is algebraic if it is the root of a finite polynomial in one variable. Hence you need show $4^{1/3}$ is the root of such a polynomial. Hmm, I wonder what such a polynomial might be .... – Simon S Apr 12 '15 at 17:40

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Is it a solution to $x^{3}-4=0$. A number is said to be algebraic over $\mathbf{Q}$ if it satisfies a polynomial in one variable over $\mathbf{Q}$, equivalently over $\mathbf{Z}$, by multiplying everything by the lcm of the denominators.

mich95
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    But don't you think that if the OP understood the question (and they mention they do not), they would be able to come up with the solution? – pjs36 Apr 12 '15 at 17:49
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    True, thanks for your point. I edited it. – mich95 Apr 12 '15 at 17:52