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I'm sure that this question is very simple, but there are no example like it in the course material and I'm not really sure what I'm looking for online.

$x_n=2^n x_{n-1}, x_0=3$

If anybody could even point me to a website that explained this, that would be great!

Thanks a lot!

Alan
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Padster
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1 Answers1

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$$x_1=2\cdot x_0\\x_2=2^2x_1=2^{2+1}x_0\\x_3=2^3x_2=2^{3+2+1}x_0\\\dots\\x_{n}=2^{n+(n-1)+\cdots+1}x_0=2^{\frac{n^2+n}{2}}x_0.$$

TZakrevskiy
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