I feel like there is something I am missing here. Is this as easy as it looks? Is the limit infinity? Or should I do L'hopital's rule?
With L'hopital I get 1/1 which is just 1.
I feel like there is something I am missing here. Is this as easy as it looks? Is the limit infinity? Or should I do L'hopital's rule?
With L'hopital I get 1/1 which is just 1.
That will work. You could also to do the following:
$$\lim_{n\to\infty}\frac n{n+1}=\lim_{n\to\infty}{n\cdot 1/n\over (n+1)\cdot 1/n=}=\lim_{n\to\infty}\frac1{1+1/n}=1.$$
Hint:
$${ n \over n+1} = 1 - {1 \over n + 1}$$
Now, what's the limit of the right hand side as $n \to \infty$?
Convert it into a middle school word problem and think. The fraction $n/(n+1)$ means $n$ parts of a thing divided into $n+1$ equal parts. Day 1 I eat piece of a pizza that was sliced into two equal parts; on day 2 I eat 2 parts from a pizza sliced into 3 equal parts; on day 99 I would be eating 99 pieces from a pizza sliced into 100 equal parts. Eventually (limit) on a single day how many pizzas would I be eating? Not really a calculus problem needing L'Hopital's rule.