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So before you guys judge me, I honestly am so clueless with this so please bare with my dumb questions.

I have been at this equation that I've been going for an hour now,

$\frac{(3x-1)}{2} -2 = 5-\frac{4x}{3+1}$ and I'm trying to solve for $x$. So I go with $6\cdot(3x-1)/2-2=(5-4x)/3 +1$ to cancel out the denominators, and I get $9x+3-6=10-8x+2$ then I move all the like terms, $9x+8x=12+9$ then my final answer is $x=21/17$

that didn't seem correct with me so then I tried, cancelling out the denominators by multiplying each side on their own number, 3 and 2. then I got $3x-1-2=5-4x+1$ and my answer is $x=9/7$

How do I go about solving this?.

Sergio Parreiras
  • 3,813
Ardine
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2 Answers2

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Your Equation looks like:
$$\frac {3x+1} {2} - 2 = 5-\frac{4x}{3+1}$$ Adding in the denominator on the right. $$\frac {3x+1} {2} - 2 = 5-\frac{4x}{4}$$ Which simplifies to $$\frac {3x+1} {2} - 2 = 5-x$$ We want to eliminate the denominator so we multiply by $2$. $$ 2\frac {3x+1} {2} - (2)2 = (2)5-(2)x$$ Simplifying $$3x+1 - 4 = 10-2x$$ Adding on the right. $$ 3x- 3 = 10-2x$$ Add $2x$ to both sides and add $3$ to both sides.

$$ 5x = 13$$ $$x=\frac{13}{5}$$

Math Man
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When you have minus or plus don't forget them. You must multiplaying all the side ! Example : (2x-1)/3+2=x 3*(2x-1)/3+3*2=3*x (2x-1)+6=3x x=5

Crapsy
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