Specialization is the name of the game in mathematics today, just as is the case in medicine. If you ever have the misfortune of breaking both a shoulder and an ankle, you'll have to talk to twenty different specialists.
There is a joke that maybe you've heard before and you'll certainly hear again. Your local university once invited the world's most renowned expert in category theory to speak at the mathematics colloquium. The presentation was a success. Afterwards, the department chair and some professors went to a restaurant. The department chair picked up the tab. "What's a 20% tip on a \$205.37 bill?" he asked, turning to the category theorist. "Don't look at me," the category theorist said, "I don't do arithmetic."
If you want to lay it on even thicker, you can extend the joke to other practical applications of mathematics for which the category theorist is utterly clueless.
But another thing that you also have to understand is that understanding advanced math in real life is quite unlike what you see on TV. There is no bomb that will blow up if you fail to properly differentiate an integral in the next five minutes. Instead, you have plenty of time to go over the definitions and notations, consult various references, and take your time pondering what it all means. In some cases, you might even be able to contact the author of the article or book and ask for clarification.
In a nutshell, understanding advanced mathematics is outwardly quite boring. Andrew Wiles spent a lot of time alone trying to solve Fermat's last theorem. And when he presented it to the public and a mistake was discovered, it took him a year to fix it, plus help from another mathematician.
Of course I should give the disclaimer that I don't actually understand advanced mathematics, though in a pinch I can bluff my way through.
P.S. Maybe you love typography more than you love mathematics... so in closing, I say unto you: $$\left(\sum_{n = \pi(\phi)}^{\infty} \frac{\phi(\pi(\phi^\pi))}{n!}\right)^{\left(\sqrt{-(\phi(\pi(\phi^\pi)))}\right) \pi}.$$