My ultimate goal is to show that $L \in PP$, but I need to figure out the title question first as an intermediary step. Any help is appreciated, thanks in advance.
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Recall that NP is closed under intersection. Hence $L_1\cap\overline{L_2}$ is in NP. Finally we can realize that the symmetric difference of this set and $L_1$ is exactly $L_1\cap L_2$.
Peter Woolfitt
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