Two hard indices questions, (what is power to a power of fraction) and (how is $(2^x)^2 = 4^x $)

Question

The answer for question 1) is $2^{3b+6}$

Question 2 I only don't get the $Y^2$ bit

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$Y^2=(2^x)^2=2^{(2x)}=(2^2)^x=4^x $ – Cbjork May 02 '15 at 23:49 — Cbjork, May 02 '15 at 23:49
This might prove useful when typesetting your questions. – May 03 '15 at 00:08 — , May 03 '15 at 00:08

score 0 · Accepted Answer · answered May 02 '15 at 23:53

0

Hint for the 1st: $\left( 4^{b+2}\right)^{\frac{3}{2}}=\left( 2^{2b+4}\right)^{\frac{3}{2}}=2^{3b+6}$.

answered May 02 '15 at 23:53

janmarqz

1 Answers1