Why is $e^x \times e^{\ln 2} = e^{x \times \ln 2}$ Not correct?
I thought that if you had something to the power, you could split them E.g $e^4 = e^2.e^2$
Sorry for the lack of latex I find it very confusing to use.
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1Well, the issue you have is that $4=2 \times 2=2+2$... So in fact $e^x \times e^y=e^{x+y}$. – Martigan May 13 '15 at 09:32
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1$e^4=(e^2)(e^2)$ is valid not because $e^4=e^{(2)(2)}$but$=e^{2+2}$ – Mythomorphic May 13 '15 at 09:33
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Ah okay, Thanks makes sense. – Tomato721 May 13 '15 at 09:34
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More ever $e^{\ln 2}= 2$ hence your statement is $2 e^x$ – Someone May 13 '15 at 09:39
