What is the sign of $-1^{\frac{2}{3}}$? I thought it was positive 1 because it involves squaring, but that doesn't seem to be the case. Why?
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If you rewrite it, it becomes $\sqrt[3]{(-1)^2}$.
$(-1)^2 = 1$ and $\sqrt[3]{1} = 1$
So positive 1.
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$x^y$ is not defined for negative $x$ and real $y$. Otherwise, we would have $(-1)^{1/3} = -1$, but $(-1)^{2/6}=1$.
Valentin
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