the unit vectors $\mathbf i$, $\mathbf j$, and $\mathbf k$ are actually vector fields
Not really. These vectors are elements of $\mathbb{R}^3$. An element of $\mathbb{R}^3$ is not the same as a map into $\mathbb{R}^3$.
Now, one can consider a constant map into $\mathbb{R}^3$ which takes the value $\mathbf i$. But... there are many such constant maps, one for each set imaginable. There is
- the constant map from $\mathbb{Z}$ to $\mathbb{R}^3$, which takes value $\mathbf i$ on every integer
- the constant map from $\mathbb{R}$ to $\mathbb{R}^3$, which takes value $\mathbf i$ on every real number
- the constant map from $\mathbb{R}^2$ to $\mathbb{R}^3$, from $\mathbb{R}^5$ to $\mathbb{R}^3$... from $[0,3]^3\times \mathbb{Z}\times \mathbb R$...
So, which one of these "is actually" $\mathbf i$? Probably none.
In some contexts it may convenient to use the same letter $\mathbf i$ for the constant map $\mathbb{R}^3\to \mathbb{R}^3$ that takes the value $\mathbf i$ everywhere. But it should be understood that this is using the same letter for a different, though related object. (A convenient abuse of notation.)
So: no, these are different things. A path is a map from $\mathbb{R}$ to $\mathbb{R}^3$.
A vector field is a map from $\mathbb{R}^3$ to $\mathbb{R}^3$ (actually, this is also an abuse of notation, which will become obvious later, when you study vector fields on manifolds).
These are very different concepts, and not just because the domains are different but because of what we do with them.