A bottle is dropped from a blimp whose height is 1200m. Assume that a= 9.81m/s/s, find the time it takes the bottle to reach the ground.
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2Just use $s=\frac{at^2}{2}$. – user26486 May 16 '15 at 13:20
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Abdullah there's a stack exchange site for physics so ask it there! – Ilaya Raja S May 16 '15 at 13:48
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2@IlayaRajaS This question would be closed as off-topic on [physics.se] – May 16 '15 at 18:50
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I say it is not off-topic because it belongs at another site. I say it is off-topic as a homework problem from a calculus course (not showing any effort on the part of the OP). – GEdgar May 17 '15 at 12:49
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Hint:
$a=\frac{\text{d}v}{\text{d}t}$
$v=\frac{\text{d}s}{\text{d}t}$
where $a$ is acceleration, $v$ is velocity, and $s$ is position.
Jay Vogler
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The position of the bottle is given by the equation: $s=s_0-\dfrac{1}{2}gt^2$ where $s_0= 1200m $ is the starting point. And it is at the ground whan $s=0$, i.e: $s_0=\dfrac{1}{2}gt^2$. Solving for $t$ you have $t=\sqrt{2s_0/g}$
Emilio Novati
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