I am (re)learning the quadratic equation. Having a concrete understanding of its purpose would really help, but I can not find any examples of a real-world scenario that requires the use of it that are more specific than "it's used by engineers" or "it's used in navigation of spacecraft." Any good real-world examples?
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Here are some, are these what you looked for http://tutorial.math.lamar.edu/Classes/Alg/QuadraticApps.aspx ? – Asinomás May 17 '15 at 18:36
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@Gamamal perfect, thank you. – Choylton B. Higginbottom May 17 '15 at 18:38
2 Answers
A few uses of quadratic equations, definitely not exhaustive. I'll provide one example for each domain.
- Economics: figuring out maximum profit from cost curves which are almost never linear.
- Athletics: figuring out what type of body movement/initial speed / way to throw a disk or ball will travel the furthest distance.
- War and Military: figuring out missile trajectories for offense as well as for interception.
- Space and Rockets: calculating a ton of information for the path of the rocket, fuel etc.
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A classic example comes up when studying motion in physics, with the kinematic equation:
$$\Delta x= {v_0} t+{1\over2}a t^2$$
being a quadratic in the time variable $t$, with initial velocity $v_0$ and acceleration $a$, both held constant. Here $\Delta x$ is the displacement, or change is distance, of an object in one dimension.
If $\Delta x$ is given, along with the constant acceleration, and initial velocity, one can use the quadratic formula to solve for $t$, the time it takes the object to travel this displacement.
Ex: Suppose a car is traveling at $40$ m/s, and then starts to accelerate at a constant $1.5$ m/s$^2$. How long will it take the car to travel $10$ m?
This gives the equation:
$$10=40t+{1\over2}\cdot1.5\cdot t^2$$
Clearing decimals and fractions, and rearranging gives:
$$3t^2+160t-40=0$$
Using the quadratic formula yields:
$$t={-160\pm\sqrt{160^2-4\cdot3\cdot(-40)}\over2\cdot3}={-160\pm\sqrt{26080}\over6}\approx0.25,-53.58$$
Since time cannot be negative, we take the positive value, so that it will take the car about a quarter of a second to travel 10 m.
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