Evaluate $\int_c f(z) dz$ from $z(0,0)$ to $z=2+4i$ where $f(z)=x^2 -iy^2$ I know how to work this out and I know the answer is $24+\frac{8}{5}i$
However I do not understand why the limits for x are $0 \to 2$ and for y are $0 \to 4$
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$z=x+iy=(x,y)$. Now $z_0=(0,0)=0+0i$ and $z_1=2+4i=(2,4)$... – b00n heT May 24 '15 at 11:41
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1I do not believe $f$ to be analytic. Then the integral between the two points is path-dependent. I take it somewhere in the problem there is a specification that the integral is to be taken over a straight line between the endpoints. – Ron Gordon May 24 '15 at 11:48