$\frac{Px}{(b-c)} = \frac{Qy}{(c-a)} = \frac{Rz}{(a-b)}$
Find the value of $(P*a*x) + (Q*b*y) + (R*c*z)$
This question is a problem of my Class VII textbook and no solved examples of the type are included.
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HINT:
Set each ratio $=k$
and put the values of $Px$ etc. in $Pax + Qby +Rcz$
lab bhattacharjee
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I don't get it. – Prithvish Baidya May 27 '15 at 05:25
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@PrithvishBaidya, $Px=k(b-c)$ right? – lab bhattacharjee May 27 '15 at 05:27
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Still don't get it – Prithvish Baidya May 27 '15 at 05:28
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@PrithvishBaidya, What is $$P\cdot a\cdot x?$$ – lab bhattacharjee May 27 '15 at 05:29
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1Can you please explain this to by imagining that you are dealing with a 10 year old. – Prithvish Baidya May 27 '15 at 05:33
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@IabBhattacharjee Can you please elaborate? – Prithvish Baidya May 27 '15 at 06:00
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@PrithvishBaidya, Can you please go through some good tutorial of ratio & proportion – lab bhattacharjee May 27 '15 at 06:06
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Just for some closure, I was actually 12 when I asked the question. I get the solution now. Thanks! – Prithvish Baidya Jul 02 '19 at 15:53
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let Px/(b−c)=Qy/(c−a)=Rz/(a−b)= k such that Px = k(b-c), Qy = k (c-a) , Rz = k(a-b) So (P∗a∗x)+(Q∗b∗y)+(R∗c∗z)= kak(b-c) + kbk (c-a) + kc*k(a-b) = 0
Kouts Km
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