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We need to divide 8 new teachers among 4 schools , how many such divisions are possible ?

I tried to solve this by the Distribution Method , that is :

$x_1$ + $x_2$ + $x_3$ + $x_4$ = 8 , which gives the solution as ${11 \choose 3}$ , is this solution correct ? Kindly help !

User9523
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    Are you allowing some schools to be empty? If you are not, then you are correct. See http://en.wikipedia.org/wiki/Stars_and_bars_%28combinatorics%29#Theorem_two_2 – Jack May 27 '15 at 11:14
  • Thanks for your reply.. Actually no further information is provided.. It just says " 8 new teachers to be divided among 4 schools.. " @Christopher – User9523 May 27 '15 at 12:57
  • Your solution is correct, just keep in mind there are 3 'bars' – Alex May 27 '15 at 14:31

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