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we know that $\tan x =\left(\frac{\text{opposite}}{\text{adjacent}}\right)$, but sometimes I see that $\tan x = (\frac{\sin x}{\cos x})$, is that the same thing or why it is different sometimes?

cause when $\tan x =\left(\frac{\text{opposite}}{\text{adjacent}}\right)$:

$\tan x = \frac{1}{2}$ - for example

but sometimes is:

$\tan x = \frac{1}{5}$ or $ \frac{2}{5}$ - if hypotenuse is $= 5$

why is that?

3 Answers3

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Roughly, they are the same definition of tangent: $$\begin{align} \require{cancel} \tan = \frac{\sin}{\cos} &= \frac{\left(\frac{\text{opposite}}{\text{hypotenuse}}\right)} {\left(\frac{\text{adjacent}}{\text{hypotenuse}}\right)} \\ &= \left(\frac{\text{opposite}}{\text{hypotenuse}}\right) \div \left(\frac{\text{adjacent}}{\text{hypotenuse}}\right) \\ &= \left(\frac{\text{opposite}}{\cancel{\text{hypotenuse}}}\right) \times \left(\frac{\cancel{\text{hypotenuse}}}{\text{adjacent}}\right) \\ &= \frac{\text{opposite}}{\text{adjacent}} \end{align}$$

Mike Pierce
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2

You may also want to search for trig explanations using the unit circle (here is an example) and see the connections between the opposite leg (height $y$) and $\sin(\theta)$, and the adjacent leg (length $x$) and $\cos(\theta)$. You'll see immediately why your two versions of tangent are the same.

Mike Pierce
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2

The relation that you write as $$ \tan x=\frac{\text{opposite}}{\text{adjacent}} $$ only holds for acute angles and was, of course, the original definition of the tangent, in times when just positive numbers were considered. Since, for acute angles we have $$ \frac{\text{opposite}}{\text{adjacent}}= \frac{\text{opposite}}{\text{hypothenuse}}\cdot \frac{\text{hypothenuse}}{\text{adjacent}}= \sin x\cdot \frac{1}{\cos x}=\frac{\sin x}{\cos x} $$ this relation has been taken as the definition of the tangent function also for any angle $x$ such that $\cos x\ne0$.

So, while the “opposite/adjacent” definition is handy for doing computations on triangles, the $“\sin x/\cos x”$ definition is better for analytic computations involving trigonometric functions. They agree for acute angles $x$ and that's the important point to note.

egreg
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