Suppose that the Bessel function is defined as: $$ J_{n}(\beta)=\frac{1}{2\pi}\int_{0}^{2\pi}e^{j(\beta\,sin\,u-nu)}du $$ Does the following integral have any relationship to the Bessel function? $$ \frac{1}{2\pi}\int_{0}^{2\pi}e^{j(\beta\,cos\,u-nu)}du $$
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$$\frac{1}{2\pi}\int_{0}^{2\pi}\exp\Big(j~\big(\beta\,\cos\,u-nu\big)\Big)~du~=~j^n~J_n\big(\beta\big).$$
Lucian
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How did you arrive at the form $j^n J_n(\beta)?$ – Purushothaman Mar 12 '20 at 16:10