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Find the area enclosed by the following graph :

$|x| +|y|=1 $

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Nalin Nehra
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    The question in the title doesn't match the question in the post. Also: what have you tried so far? –  Jun 22 '15 at 06:50
  • Though I think you meant the one in the title. –  Jun 22 '15 at 06:51

1 Answers1

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Assuming $|x|+|y|=1$

the straight lines are $x+y=1,x-y=1,-x-y=1,-x+y=1$

which form a square with each side $=\sqrt{(1-0)^2+(0-1)^2}$

or form four equal right isosceles triangles with each equal side $1$ unit

so, each has area $=\dfrac12\cdot1\cdot1$ sq. unit Therefore area of area enclosed is 1/2 * 4 = 2 units

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lab bhattacharjee
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