-1

I have 8 groups, each each group has 3 distinct elements, must select 1 element from each group.

How many unique arrangements can I make, selecting 1 element (of 3 choices) from 8 groups?

Is it simply $n=8 r=3$ therefore $\frac{8!}{5!3!} = 56$ .

Thanks for the help folks!

mich95
  • 8,713
James
  • 1

1 Answers1

0

Hint: Is there any overlap between the groups? If not, each choice has three options. If so, you need to specify.

Ross Millikan
  • 374,822