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A,B,C are employed to do a piece of work for Rs 5290. A and B together are supposed to do 19/23 th of the work and B and C together 8/23 th of the work then A should be paid

A.Rs 4250

B.Rs 3450

C.Rs 1950

D.Rs 2290

sir can you tell me how to solve this

2 Answers2

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We're going to write $A,B,C$ for the fraction of the total work that each person does. We are given that $$A+B=\frac{19}{23}$$ $$B+C=\frac{8}{23}$$ And we finally impose $$A+B+C=1$$ as they must sum to 1. Really we only need the last 2 equations. We substitute the second into the 3rd to give $A+\frac{8}{23}=1$, i.e. $A=1-\frac{8}{23}=\frac{15}{23}$. So $A$ should be paid $\frac{15}{23}*5290=3450$

Mar5bar
  • 387
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Have you reproduced the question exactly ? As it stands, it makes little sense.

However, interpreting that in a certain time, A and B working together can do 19/23 of the work, while B and C (in the same time) can do 8/23 of the work, we can write two equations

A + B = 19/23

B + C = 8/23

Adding the two, A + 2B + C = 27/23

Assuming that A,B and C together would just complete the work in the given time, B can complete only 27/23 - 23/23 = 4/23 of the work, and A can complete 19/23 - 4/23 = 15/23 of the work.

Thus A's pay should be $\frac{15}{23}\cdot 5290 =3450 $