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I know I have to use the properties of the trigonometric functions but I don't know which of them would help me get the answer.

2 Answers2

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$y + 3 = \cos (2t) = 2\cos^2t-1 = 2x^2-1\to y = 2x^2-4$. So if you want to find $\dfrac{dy}{dx}$ then from this $y' = 4x$

DeepSea
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Hint: Use chain rule: $\frac{dy}{dx}=\frac{dy}{dt} \times \frac{dt}{dx}$. First find $\frac{dy}{dt}$ and $\frac{dx}{dt}$.

Chuks
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