No, you shouldn't think of the total derivative as a rate of change. The generalisation of the concept of the derivative follows from another perspective of understanding it.
One can see it is a rate of change from the following:
$f'(x)=\lim_{h\to0}\frac{f(x+h)-f(x)}{h}$ which is the same as $\lim_{\Delta x\to0}\frac{\Delta y}{\Delta x} $.
However, this leads to some deeply related concept, approximating through a linear function. (You'd see this easily if you knew some Taylor series)
$f'(x)=\lim_{h\to0}\frac{f(x+h)-f(x)}{h}$
This means that
$f'(x)h=f(x+h)-f(x)+\epsilon(h)$ where $\frac{\epsilon(h)}{h}\to0$ as $h\to0$.
This means that $f'(x)h$ is the best linear approximation of $\Delta y$ in a neighbourhood of x.
Now, you can also see $f'(x)h$ not as a number, but as a linear transformation in $h$. This is because we have linear approximations by a line in $\mathbb{R}^1$ whereas the natural generalisation of linear functions is linear transformations.
Now, through the definition of the total derivative, the total derivative $A$ of $f$ at $x$ is the best approximation that satisfies
$f(x+h)-f(x)=A(h)+\epsilon(h)$ where $\frac{|\epsilon(h)|}{|h|}\to0$ as $h\to0$.
That is $A(h)$ is the best linear approximation of $\Delta y$ in a neighborhood of $x$.
As for the partial derivatives, you can think of them like rates of change because all variables are fixed except one, that is you can think of the rate of change of the function as we move in one direction.
I hope this helps.