Solve $6^{5/2}$ $\left(\dfrac{3}2\right)^{-3/2}$ where i get $6^{5/2}$ *$\dfrac{3^{-3/2}}{2^{-3/2}}\cdot$ which i get to $6^{5/2}$ *$\dfrac{2^{3/2}}{3^{3/2}}\cdot$ which leads to $\dfrac{12^{8/2}}{3^{3/2}}\cdot$ that i get to $4^{5/2}$. Can you show me where this is wrong?
Asked
Active
Viewed 25 times
0
-
3$6^{5/2}\cdot 2^{3/2} \ne 12^{8/2}$ – Michael Galuza Jul 27 '15 at 14:24
1 Answers
0
HINT: it is $$\frac{6^{5/2}\cdot 2^{3/2}}{3^{3/2}}=\frac{2^{5/2}\cdot 3^{5/2}\cdot 2^{3/2}}{3^{3/2}}=2^4\cdot 3$$
Dr. Sonnhard Graubner
- 95,283