I just came across this question and thought if i could ask help. How do you solve problems that have powers with a negative number? Ex. 2^(-2)
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1https://en.wikipedia.org/wiki/Exponentiation – JRN Jul 31 '15 at 04:35
1 Answers
The effect of the minus sign in the exponent is to invert the remaining expression. For example, $2^{-3}=\frac1{2^3}$. Since $2^3$ is $8$, that means $2^{-3}=\frac1{2^3}=\frac18$.
The justification is that this preserves the ordinary laws of exponents, such as $$x^a\cdot x^b=x^{a+b}$$ regardless of the sign of $a$ or $b$.
Addenda: One can assume the above law holds, and derive the desired result (and others).
For example, to determine what $x^0$ must mean, one could proceeds as follows.
$$x=x^1=x^{0+1}=\boxed{x^0}\cdot x^1=\boxed{x^0}\cdot x$$ That is, $$x=\boxed{x^0}\cdot x$$ Dividing both sides by $x$ yields that $x^0$ must be $1$ if it means anything.
Then it follows that $$1=x^0=x^{-n+n}=\boxed{x^{-n}}\cdot x^n$$ That is, $$1=\boxed{x^{-n}}\cdot x^n$$ and dividing by $x^n$ gives that $$\boxed{x^{-n}}= \frac{1}{x^n}$$
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