Prove that: $$ (a<b<c) \implies (a<\frac{a+b+c}{3}<c) $$ I'm having problem proving these implications (I don't know how they're called in English). Can you tell me what I have to read to understand these?
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HINT:
$a<b<c\implies 3a=a+a+a<a+b+c$
and $3c=c+c+c>c+b+a$
Conrado Costa
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lab bhattacharjee
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I'm sorry, I don't understand. How did you come up with $a+a+a<a+b+c$? – Gjekaks Aug 17 '15 at 16:34
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$a\lt b, a\lt c$ – Eleven-Eleven Aug 17 '15 at 16:35
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@Eleven-Eleven oh, yeah! Thanks. – Gjekaks Aug 17 '15 at 16:38