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solve the following system of equations numerically $$2x+2y - e^{xy} = 0$$ $$x^3 + y - xy^3 = 1$$

I'm also asked to solve analytically but I'm pretty sure the closed form solution doesn't exist because if yes, then the second equation would involve Cardano formula, plus the log/exponential form from the top, it doesn't look closed to me.

I know if there is a solution, then it shouldn't lie in the quadrant $x<0,y<0$ because from the first equation $x+y>0$ implies either $x>0$ or $y>0$. However, I don't know how to solve completely.

thanks for any help!

kensaii
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1 Answers1

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a numerical method is useful to solve this system, the only way that i have in mind is to solve the second equation for $x$ or $y$ and with the first equation you got an equation in $x$ or $y$ which you can solve also by the Newton method, i have found $$x \approx 1.059396315, y \approx -.8579048919$$